G(x)=x^2-25F(x)=2x+5

Solution for G(x)=x^2-25F(x)=2x+5 equation:

(G)=G^2-25(G)=2G+5

We move all terms to the left:

(G)-(G^2-25(G))=0

We get rid of parentheses

-G^2+G+25G=0

We add all the numbers together, and all the variables

-1G^2+26G=0

a = -1; b = 26; c = 0;
Δ = b2-4ac
Δ = 262-4·(-1)·0
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$G_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$G_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$G_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-26}{2*-1}=\frac{-52}{-2}
=+26
$
$G_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+26}{2*-1}=\frac{0}{-2}
=0
$